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From: Ramkumar Ramachandra <artagnon@gmail.com>
Date: Thu, 26 Sep 2013 18:43:16 +0530
Message-ID: <CALkWK0ndMtyQxE0uK4H-Ly6oy+tRn-SFc=_1WoC2QAp2uy0dtw@mail.gmail.com>
Subject: Re: [PATCH 2/8] um: Do not use SUBARCH
To: Richard Weinberger <richard@nod.at>
Cc: linux-arch@vger.kernel.org, Michal Marek <mmarek@suse.cz>,
        geert@linux-m68k.org, ralf@linux-mips.org, lethal@linux-sh.org,
        Jeff Dike <jdike@addtoit.com>, Guan Xuetao <gxt@mprc.pku.edu.cn>,
        Thomas Gleixner <tglx@linutronix.de>, Ingo Molnar <mingo@redhat.com>,
        "H. Peter Anvin" <hpa@zytor.com>, x86@kernel.org,
        linux-kbuild@vger.kernel.org, LKML <linux-kernel@vger.kernel.org>,
        linux-m68k@vger.kernel.org, linux-mips@linux-mips.org,
        linux-sh@vger.kernel.org, user-mode-linux-devel@lists.sourceforge.net
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Ramkumar Ramachandra wrote:
> Richard Weinberger wrote:
>> I told you already that "make defconfig ARCH=um SUBARCH=x86" will spuriously
>> create a x86_64 config on x86_64.
>> This breaks existing setups.
>
> I'll fix this and resubmit soon.

Wait a minute. You're now arguing about whether the generic "x86"
means i386 or x86_64. Its meaning is already defined in
arch/x86/Kconfig and arch/x86/um/Kconfig: see the config 64BIT. Unless
i386 is explicitly specified, the default is to build a 64-bit kernel.
That is already defined for a normal Linux kernel, and user-mode Linux
should not break that convention. So, in the example you pulled out of
your hat:

  $ make defconfig ARCH=um SUBARCH=x86

the user should expect a 64-bit build, and not an i386 build as you
say. Both my patches are correct, and the "regression" that you
pointed out is a red herring.
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