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Date: Thu, 8 Feb 2001 21:09:49 -0800 (PST)
From: dean gaudet <dean-list-linux-kernel@arctic.org>
To: <linux-kernel@vger.kernel.org>
Subject: ARP out the wrong interface
Message-ID: <Pine.LNX.4.33.0102082058060.21439-100000@twinlark.arctic.org>
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this appears to occur with both 2.2.16 and 2.4.1.

server:

eth0 is 192.168.250.11 netmask 255.255.255.0
eth1 is 192.168.251.11 netmask 255.255.255.0

they're both connected to the same switch.

client:

eth0 is 192.168.251.11 netmask 255.255.255.0

connected to the same switch as both of server's eth.

on client i try "ping 192.168.251.11".

responses come back from both eth0 and eth1, listing each of their
respective MAC addresses...  it's essentially a race condition at this
point as to whether i'll get the right MAC address.  ("right" means the
MAC for server:eth1).

client# tcpdump -n arp
Kernel filter, protocol ALL, datagram packet socket
tcpdump: listening on all devices
21:03:05.695089 eth0 > arp who-has 192.168.251.11 tell 192.168.251.25 (0:3:47:0:25:80)
21:03:05.695405 eth0 < arp reply 192.168.251.11 is-at 0:d0:b7:be:3e:aa (0:3:47:0:25:80)
21:03:05.695523 eth0 < arp reply 192.168.251.11 is-at 0:d0:b7:1f:ea:35 (0:3:47:0:25:80)


server# cat /proc/sys/net/ipv4/ip_forward
0
server# cat /proc/sys/net/ipv4/conf/*/proxy_arp
0
0
0
0
0
0
0

is this expected?  it seems broken.

thanks
-dean

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