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From: Torsten Foertsch <torsten.foertsch@gmx.net>
To: Christoph Hellwig <hch@infradead.org>
Subject: Re: [2.4.19] How to get the path name of a struct dentry
Date: Wed, 12 Mar 2003 14:32:47 +0100
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References: <200303121033.08560.torsten.foertsch@gmx.net> <20030312104741.A9625@infradead.org> <200303121404.04979.torsten.foertsch@gmx.net>
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On Wednesday 12 March 2003 14:04, Torsten Foertsch wrote:
> On Wednesday 12 March 2003 11:47, Christoph Hellwig wrote:
> > On Wed, Mar 12, 2003 at 11:38:27AM +0100, Torsten Foertsch wrote:
> > > Next question, is there a way to get the dentry and vfsmount of /? I
> > > mean not current->fs->root and current->fs->rootmnt. They can be
> > > chrooted. I mean the real /.
> >
> > No.  Esecially as there is not single "real" root.
>
> How about that slightly modified d_path()?
>
> char*
> full_d_path( struct dentry *dentry,
> 	     struct vfsmount *vfsmnt,
> 	     char *buf, int buflen ) {
...
> }

or even simpler

char*
full_d_path( struct dentry *dentry,
	     struct vfsmount *vfsmnt,
	     char *buf, int buflen ) {
  char *res;
  struct vfsmount *rootmnt;
  struct dentry *root;
  struct namespace *ns;

  ns=current->namespace;
/*   get_namespace( ns ); */
  rootmnt=mntget( ns->root );
/*   put_namespace( ns ); */

  root = dget(rootmnt->mnt_root);

  spin_lock(&dcache_lock);
  res = __d_path(dentry, vfsmnt, root, rootmnt, buf, buflen);
  spin_unlock(&dcache_lock);

  dput(root);
  mntput(rootmnt);
  return res;
}

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