Return-Path: Received: (majordomo@vger.kernel.org) by vger.kernel.org via listexpand id S936705AbdLRQpI (ORCPT ); Mon, 18 Dec 2017 11:45:08 -0500 Received: from bombadil.infradead.org ([65.50.211.133]:42960 "EHLO bombadil.infradead.org" rhost-flags-OK-OK-OK-OK) by vger.kernel.org with ESMTP id S934853AbdLRQpD (ORCPT ); Mon, 18 Dec 2017 11:45:03 -0500 Date: Mon, 18 Dec 2017 17:44:49 +0100 From: Peter Zijlstra To: Crt Mori Cc: Jonathan Cameron , Ingo Molnar , Andrew Morton , Kees Cook , Rusty Russell , Ian Abbott , Larry Finger , Niklas Soderlund , Thomas Gleixner , Krzysztof Kozlowski , Masahiro Yamada , linux-kernel@vger.kernel.org, linux-iio@vger.kernel.org Subject: Re: [PATCH v6 1/3] lib: Add strongly typed 64bit int_sqrt Message-ID: <20171218164449.dtdgk2bvnl4nbjcm@hirez.programming.kicks-ass.net> References: <20171218150544.8000-1-cmo@melexis.com> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline In-Reply-To: <20171218150544.8000-1-cmo@melexis.com> User-Agent: NeoMutt/20170609 (1.8.3) Sender: linux-kernel-owner@vger.kernel.org List-ID: X-Mailing-List: linux-kernel@vger.kernel.org Content-Length: 1091 Lines: 42 On Mon, Dec 18, 2017 at 04:05:44PM +0100, Crt Mori wrote: > There is no option to perform 64bit integer sqrt on 32bit platform. > Added stronger typed int_sqrt64 enables the 64bit calculations to > be performed on 32bit platforms. Although int_sqrt() is a rough > approximation, the same algorithm is used in int_sqrt64() as good > enough on 32bit platform. You clearly haven't read a recent version of the file you're patching. Please take a moment to do so now. > +/** > + * int_sqrt64 - strongly typed int_sqrt function > + * @x: 64bit integer of which to calculate the sqrt > + */ > +u64 int_sqrt64(u64 x) Please explain how the result of sqrt(u64) can be larger than u32. Also, I expect that this fact could be exploited to optimize this for 32bit archs if one were so inclined. > +{ > + u64 b, m, y = 0; > + > + if (x <= 1) > + return x; > + > + m = 1ULL << (64 - 2); > + while (m != 0) { > + b = y + m; > + y >>= 1; > + > + if (x >= b) { > + x -= b; > + y += m; > + } > + m >>= 2; > + } > + return y; > +} so yeah, no, please try again after reading the current file.