Date: Thu, 11 Nov 2004 16:37:31 +0300
Message-Id: <200411111337.iABDbVts000788@blacklife.kmv.ru>
From: Andrey Melnikoff <temnota+news@kmv.ru>
To: Willy Tarreau <willy@w.ods.org>, linux-kernel@vger.kernel.org
Subject: Re: [2.4.28-rc1] process stuck in release_task() call
In-Reply-To: <20041111083312.GE783@alpha.home.local>
User-Agent: tin/1.7.6-20040906 ("Baleshare") (UNIX) (Linux/2.6.6-rc1 (i686))
Sender: linux-kernel-owner@vger.kernel.org
Content-Length: 1575
Lines: 42

Hello Willy Tarreau!
 In article <20041111083312.GE783@alpha.home.local> you wrote:

> > > >>EIP; c012073d <release_task+1fd/230>   <=====
> (...)
> > > c0120540 <release_task>:
> > > c0120540:       55                      push   %ebp
> > > ....
> > > c0120736:       89 d8                   mov    %ebx,%eax
> > > c0120738:       e8 73 dd 01 00          call   c013e4b0 <free_pages> <= here
> > 
> > is this release_task+1fd?  Can you send me the full disassemble of release_task?

> Yes it is because the next instruction after call will be at c0120738+5 =
> c012073d = release_task+1fd. (the return address on the stack is the
> address of the next instruction after the call).

> > It can't be blocked here, its a "call" instruction. 

> Seems rather strange indeed ! Perhaps this is not the disassembled function
> of the *running* kernel ? 

This is also strange for me. Stack trace should point into __free_pages_ok() 
address space. Only this function work with lock's.

> it would be good to disassemble vmlinux and ensure that it is exactly 
> the one currently running. 

This is code from vmlinux-2.4.28-rc1.

> I too have already lost lots of time searching a wrong bug because I 
> disassembled the wrong kernel, so I'm certain it can happen even when 
> we're very careful :-(

[skipp]

PS: Please, keep CC: to me.
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