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If so, a divide-by-zero bug will occur: remainder = do_div(d, divisor); Also, in the function mega_div64_32(), a divide-by-zero bug can also occur if divisor is NULL. To fix these divide-by-zero bugs, the functions return 0 if divisor is zero. Reported-by: TOTE Robot Signed-off-by: Tuo Li --- drivers/scsi/megaraid/megaraid_sas_fp.c | 8 ++++++-- 1 file changed, 6 insertions(+), 2 deletions(-) diff --git a/drivers/scsi/megaraid/megaraid_sas_fp.c b/drivers/scsi/megaraid/megaraid_sas_fp.c index 83f69c33b01a..05eb0d201aed 100644 --- a/drivers/scsi/megaraid/megaraid_sas_fp.c +++ b/drivers/scsi/megaraid/megaraid_sas_fp.c @@ -72,8 +72,10 @@ u32 mega_mod64(u64 dividend, u32 divisor) u64 d; u32 remainder; - if (!divisor) + if (!divisor) { printk(KERN_ERR "megasas : DIVISOR is zero, in div fn\n"); + return 0; + } d = dividend; remainder = do_div(d, divisor); return remainder; @@ -90,8 +92,10 @@ static u64 mega_div64_32(uint64_t dividend, uint32_t divisor) { u64 d = dividend; - if (!divisor) + if (!divisor) { printk(KERN_ERR "megasas : DIVISOR is zero in mod fn\n"); + return 0; + } do_div(d, divisor); -- 2.25.1