Date: Sun, 18 Feb 2007 17:04:01 +0100
From: Jean Delvare <khali@linux-fr.org>
To: "H. Peter Anvin" <hpa@zytor.com>
Cc: Linus Torvalds <torvalds@linux-foundation.org>,
       Dax Kelson <dax@gurulabs.com>,
       linux-kernel <linux-kernel@vger.kernel.org>
Subject: Re: Linus' laptop and Num lock status
Message-Id: <20070218170401.286e0fc6.khali@linux-fr.org>
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	<45D46F7B.3060105@zytor.com>
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On Thu, 15 Feb 2007 06:34:35 -0800, H. Peter Anvin wrote:
> Jean Delvare wrote:
> > On x86, the BIOS led state can be read from byte 0x97 the BIOS RAM. The
> > BIOS RAM is mapped at 0x400 so all we need to do is to one byte from
> > RAM (offset 0x497). This is how Suse's hwinfo does.
> 
> Perhaps that's what Suse does, but the proper address is 0x417.
> 
> 0x497 is the rarely-used LPT2 timeout counter.

Still, the information printed by hwinfo is correct, I've tested it
myself. Is there some publicly available documentation about the x86
BIOS RAM mapping?

Thanks,
-- 
Jean Delvare
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