Date:   Mon, 30 Jan 2023 19:51:01 +0000
From:   Andrei Gherzan <andrei.gherzan@canonical.com>
To:     Willem de Bruijn <willemb@google.com>
Cc:     Paolo Abeni <pabeni@redhat.com>,
        "David S. Miller" <davem@davemloft.net>,
        Eric Dumazet <edumazet@google.com>,
        Jakub Kicinski <kuba@kernel.org>,
        Shuah Khan <shuah@kernel.org>, netdev@vger.kernel.org,
        linux-kselftest@vger.kernel.org, linux-kernel@vger.kernel.org
Subject: Re: [PATCH] selftests: net: udpgso_bench_tx: Introduce exponential
 back-off retries
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On 23/01/30 06:24PM, Andrei Gherzan wrote:
> On 23/01/30 12:35PM, Willem de Bruijn wrote:
> > On Mon, Jan 30, 2023 at 12:31 PM Andrei Gherzan
> > <andrei.gherzan@canonical.com> wrote:
> > >
> > > On 23/01/30 11:29AM, Willem de Bruijn wrote:
> > > > On Mon, Jan 30, 2023 at 11:23 AM Andrei Gherzan
> > > > <andrei.gherzan@canonical.com> wrote:
> > > > >
> > > > > On 23/01/30 04:15PM, Andrei Gherzan wrote:
> > > > > > On 23/01/30 11:03AM, Willem de Bruijn wrote:
> > > > > > > On Mon, Jan 30, 2023 at 9:28 AM Andrei Gherzan
> > > > > > > <andrei.gherzan@canonical.com> wrote:
> > > > > > > >
> > > > > > > > On 23/01/30 08:35AM, Willem de Bruijn wrote:
> > > > > > > > > On Mon, Jan 30, 2023 at 7:51 AM Andrei Gherzan
> > > > > > > > > <andrei.gherzan@canonical.com> wrote:
> > > > > > > > > >
> > > > > > > > > > On 23/01/30 09:26AM, Paolo Abeni wrote:
> > > > > > > > > > > On Fri, 2023-01-27 at 17:03 -0500, Willem de Bruijn wrote:
> > > > > > > > > > > > On Fri, Jan 27, 2023 at 1:16 PM Andrei Gherzan
> > > > > > > > > > > > <andrei.gherzan@canonical.com> wrote:
> > > > > > > > > > > > >
> > > > > > > > > > > > > The tx and rx test programs are used in a couple of test scripts including
> > > > > > > > > > > > > "udpgro_bench.sh". Taking this as an example, when the rx/tx programs
> > > > > > > > > > > > > are invoked subsequently, there is a chance that the rx one is not ready to
> > > > > > > > > > > > > accept socket connections. This racing bug could fail the test with at
> > > > > > > > > > > > > least one of the following:
> > > > > > > > > > > > >
> > > > > > > > > > > > > ./udpgso_bench_tx: connect: Connection refused
> > > > > > > > > > > > > ./udpgso_bench_tx: sendmsg: Connection refused
> > > > > > > > > > > > > ./udpgso_bench_tx: write: Connection refused
> > > > > > > > > > > > >
> > > > > > > > > > > > > This change addresses this by adding routines that retry the socket
> > > > > > > > > > > > > operations with an exponential back off algorithm from 100ms to 2s.
> > > > > > > > > > > > >
> > > > > > > > > > > > > Fixes: 3a687bef148d ("selftests: udp gso benchmark")
> > > > > > > > > > > > > Signed-off-by: Andrei Gherzan <andrei.gherzan@canonical.com>
> > > > > > > > > > > >
> > > > > > > > > > > > Synchronizing the two processes is indeed tricky.
> > > > > > > > > > > >
> > > > > > > > > > > > Perhaps more robust is opening an initial TCP connection, with
> > > > > > > > > > > > SO_RCVTIMEO to bound the waiting time. That covers all tests in one
> > > > > > > > > > > > go.
> > > > > > > > > > >
> > > > > > > > > > > Another option would be waiting for the listener(tcp)/receiver(udp)
> > > > > > > > > > > socket to show up in 'ss' output before firing-up the client - quite
> > > > > > > > > > > alike what mptcp self-tests are doing.
> > > > > > > > > >
> > > > > > > > > > I like this idea. I have tested it and it works as expected with the
> > > > > > > > > > exeception of:
> > > > > > > > > >
> > > > > > > > > > ./udpgso_bench_tx: sendmsg: No buffer space available
> > > > > > > > > >
> > > > > > > > > > Any ideas on how to handle this? I could retry and that works.
> > > > > > > > >
> > > > > > > > > This happens (also) without the zerocopy flag, right? That
> > > > > > > > >
> > > > > > > > > It might mean reaching the sndbuf limit, which can be adjusted with
> > > > > > > > > SO_SNDBUF (or SO_SNDBUFFORCE if CAP_NET_ADMIN). Though I would not
> > > > > > > > > expect this test to bump up against that limit.
> > > > > > > > >
> > > > > > > > > A few zerocopy specific reasons are captured in
> > > > > > > > > https://www.kernel.org/doc/html/latest/networking/msg_zerocopy.html#transmission.
> > > > > > > >
> > > > > > > > I have dug a bit more into this, and it does look like your hint was in
> > > > > > > > the right direction. The fails I'm seeing are only with the zerocopy
> > > > > > > > flag.
> > > > > > > >
> > > > > > > > From the reasons (doc) above I can only assume optmem limit as I've
> > > > > > > > reproduced it with unlimited locked pages and the fails are transient.
> > > > > > > > That leaves optmem limit. Bumping the value I have by default (20480) to
> > > > > > > > (2048000) made the sendmsg succeed as expected. On the other hand, the
> > > > > > > > tests started to fail with something like:
> > > > > > > >
> > > > > > > > ./udpgso_bench_tx: Unexpected number of Zerocopy completions:    774783
> > > > > > > > expected    773707 received
> > > > > > >
> > > > > > > More zerocopy completions than number of sends. I have not seen this before.
> > > > > > >
> > > > > > > The completions are ranges of IDs, one per send call for datagram sockets.
> > > > > > >
> > > > > > > Even with segmentation offload, the counter increases per call, not per segment.
> > > > > > >
> > > > > > > Do you experience this without any other changes to udpgso_bench_tx.c.
> > > > > > > Or are there perhaps additional sendmsg calls somewhere (during
> > > > > > > initial sync) that are not accounted to num_sends?
> > > > > >
> > > > > > Indeed, that looks off. No, I have run into this without any changes in
> > > > > > the tests (besides the retry routine in the shell script that waits for
> > > > > > rx to come up). Also, as a data point.
> > > > >
> > > > > Actually wait. I don't think that is the case here. "expected" is the
> > > > > number of sends. In this case we sent 1076 more messages than
> > > > > completions. Am I missing something obvious?
> > > >
> > > > Oh indeed.
> > > >
> > > > Receiving fewer completions than transmission is more likely.
> > >
> > > Exactly, yes.
> > >
> > > > This should be the result of datagrams still being somewhere in the
> > > > system. In a qdisc, or waiting for the network interface to return a
> > > > completion notification, say.
> > > >
> > > > Does this remain if adding a longer wait before the final flush_errqueue?
> > >
> > > Yes and no. But not realiably unless I go overboard.
> > >
> > > > Or, really, the right fix is to keep polling there until the two are
> > > > equal, up to some timeout. Currently flush_errqueue calls poll only
> > > > once.
> > >
> > > That makes sense. I have implemented a retry and this ran for a good
> > > while now.
> > >
> > > -               flush_errqueue(fd, true);
> > > +               while (true) {
> > > +                       flush_errqueue(fd, true);
> > > +                       if ((stat_zcopies == num_sends) || (delay >= MAX_DELAY))
> > > +                               break;
> > > +                       usleep(delay);
> > > +                       delay *= 2;
> > > +               }
> > >
> > > What do you think?
> > 
> > Thanks for running experiments.
> > 
> > We can avoid the unconditional sleep, as the poll() inside
> > flush_errqueue already takes a timeout.
> > 
> > One option is to use start_time = clock_gettime(..) or gettimeofday
> > before poll, and restart poll until either the exit condition or
> > timeout is reached, with timeout = orig_time - elapsed_time.
> 
> Yes, this was more of a quick draft. I was thinking to move it into the
> flush function (while making it aware of num_sends via a parameter):
> 
> if (do_poll) {
>   struct pollfd fds = {0};
>   int ret;
>   unsigned long tnow, tstop;
> 
>   fds.fd = fd;
>   tnow = gettimeofday_ms();
>   tstop = tnow + POLL_LOOP_TIMEOUT_MS;
>   while ((stat_zcopies != num_sends) && (tnow < tstop)) {
>     ret = poll(&fds, 1, 500);
>     if (ret == 0) {
>       if (cfg_verbose)
>         fprintf(stderr, "poll timeout\n");
>       } else if (ret < 0) {
>         error(1, errno, "poll");
>     }
>     tnow = gettimeofday_ms();
>   }
> }
> 
> Does this make more sense?

Obviously, this should be a do/while. Anyway, this works as expected
after leaving it for a around two hours.

-- 
Andrei Gherzan