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charset=UTF-8 Content-Transfer-Encoding: 8bit On 26/01/2024 13:28, Théo Lebrun wrote: >>> >>> pinctrl0: pinctrl-a { >>> compatible = "mobileye,eyeq5-a-pinctrl"; >>> reg = <0x0B0 0x30>; >>> }; >>> >>> pinctrl1: pinctrl-b { >>> compatible = "mobileye,eyeq5-b-pinctrl"; >>> reg = <0x0B0 0x30>; >> >> Duplicate reg? > > Yes, the mapping is intertwined. Else it could be three ressources per > pinctrl. Just really small ones. > > - 0xB0 mapping A > - 0xB4 mapping B > - 0xB8 > - 0xBC > - 0xC0 pull-down A > - 0xC4 pull-up A > - 0xC8 pull-down B > - 0xCC pull-up B > - 0xD0 drive-strength lo A > - 0xD4 drive-strength hi A > - 0xD8 drive-strength lo B > - 0xDC drive-strength hi B > > 0xB8 is unrelated (I2C speed & SPI CS). 0xBC is a hole. Then maybe Rob's idea of one pinctrl device is better... Best regards, Krzysztof