Message-ID: <20080626205650.9ifra13zswgoo0ow@webmail1.sjtu.edu.cn>
Date: Thu, 26 Jun 2008 20:56:50 +0800
From: =?gb2312?b?z8TBwQ==?= <xiaiaxaxi@sjtu.edu.cn>
To: linux-kernel@vger.kernel.org
Subject: Can I use yield in this way
MIME-Version: 1.0
Content-Type: text/plain;
	charset=GB2312;
	DelSp="Yes";
	format="flowed"
Content-Disposition: inline
Content-Transfer-Encoding: 7bit
User-Agent: Internet Messaging Program (IMP) H3 (4.1.3)
Sender: linux-kernel-owner@vger.kernel.org

Hello,

        I'd like to ask a question about the use of a kernel function,  
yield(); I am working on Intel Core Duo, running Linux 2.6.21 I want  
to let current process be off the cpu when the temperature of cpu is  
too high. I add a function called thermal_balance in the timer  
interrupt. My program is as following,

scheduler_tick()
{
       static int count = 0;
       count++;
       if(count % 100 == 0)
           thermal_balance();
}

static int thermal_balance(void)
{
       int cpu = smp_processor_id();
       struct task_struct* task;
       Get CPU temperature.

       if (temperature is too high){
               task = cpu_rq(cpu)->curr;
               yield();
               Move task to other cpu.
       }
}

       Can yield() be used as above. After I compile the kernel and  
run again. Kernel is not working just as it meets deadlock. And if I  
comment yield(), it runs ok. Could anyone help me?Thanks!

--
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to majordomo@vger.kernel.org
More majordomo info at  http://vger.kernel.org/majordomo-info.html
Please read the FAQ at  http://www.tux.org/lkml/