Return-Path: Received: (majordomo@vger.kernel.org) by vger.kernel.org via listexpand id ; Tue, 5 Mar 2002 22:55:12 -0500 Received: (majordomo@vger.kernel.org) by vger.kernel.org id ; Tue, 5 Mar 2002 22:55:02 -0500 Received: from x35.xmailserver.org ([208.129.208.51]:27406 "EHLO x35.xmailserver.org") by vger.kernel.org with ESMTP id ; Tue, 5 Mar 2002 22:54:54 -0500 X-AuthUser: davidel@xmailserver.org Date: Tue, 5 Mar 2002 19:58:24 -0800 (PST) From: Davide Libenzi X-X-Sender: davide@blue1.dev.mcafeelabs.com To: Ben Greear cc: linux-kernel Subject: Re: a faster way to gettimeofday? In-Reply-To: <3C859007.50102@candelatech.com> Message-ID: MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII Sender: linux-kernel-owner@vger.kernel.org X-Mailing-List: linux-kernel@vger.kernel.org On Tue, 5 Mar 2002, Ben Greear wrote: > I have a program that I very often need to calculate the current > time, with milisecond accuracy. I've been using gettimeofday(), > but gprof shows it's taking a significant (10% or so) amount of > time. Is there a faster (and perhaps less portable?) way to get > the time information on x86? My program runs as root, so should > have any permissions it needs to use some backdoor hack if that > helps! If you're on x86 you can use collect rdtsc samples and convert them to ms. You'll get even more then ms accuracy. - Davide - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to majordomo@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/