Date: Mon, 15 Jun 2009 01:45:46 +0200
From: "Hans J. Koch" <hjk@linutronix.de>
To: Alan Cox <alan@lxorguk.ukuu.org.uk>
Cc: "Hans J. Koch" <hjk@linutronix.de>, Wolfram Sang <w.sang@pengutronix.de>,
       linux-kernel@vger.kernel.org, linuxppc-dev@ozlabs.org,
       devicetree-discuss@ozlabs.org, Magnus Damm <magnus.damm@gmail.com>,
       Greg KH <gregkh@suse.de>
Subject: Re: [PATCH 2/2] uio: add an of_genirq driver
Message-ID: <20090614234546.GJ3639@local>
References: <1244765062-14144-1-git-send-email-w.sang@pengutronix.de> <1244765062-14144-3-git-send-email-w.sang@pengutronix.de> <20090614122136.GD3639@local> <20090615001207.1829e7b5@lxorguk.ukuu.org.uk>
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On Mon, Jun 15, 2009 at 12:12:07AM +0100, Alan Cox wrote:
> > > +	if (!uioinfo->irq)
> > > +		uioinfo->irq = UIO_IRQ_NONE;
> > 
> > Please don't do this. It's inconsistent if all other UIO drivers require
> > people to use UIO_IRQ_NONE and you also allow zero. UIO_IRQ_NONE was
> > introduced because 0 may be a legal interrupt number on some platforms.
> 
> Zero is not a valid IRQ number in the kernel (except in arch specific
> depths). IRQ numbers are also *unsigned* so -1 isn't a safe definition.

The above uioinfo->irq is a signed long.

> 
> Zero means no IRQ. If any old UIO code is assuming otherwise it wants
> fixing.

It doesn't. It won't complain about IRQ 0 and will pass it on to
request_irq, which will probably fail if it is as you say.

I did it that way because I saw IRQ 0 in /proc/interrupts on every PC...

> 
> It is the job of the platform to map a physical IRQ 0 to some other
> representation if it exists outside of arch specific code.

Funny.

> This was
> decided some years ago and a large part of the kernel simply doesn't
> support any notion of a real IRQ 0.

Can you tell me the reason for that decision or point me to some ml archive?

Thanks,
Hans

> 
> Alan
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