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From: "Anthony Chee" <anthony.chee@polyu.edu.hk>
To: =?iso-8859-1?Q?Peter_W=E4chtler?= <pwaechtler@loewe-komp.de>
Cc: <linux-kernel@vger.kernel.org>
In-Reply-To: <000901c1e2f1$e65e9b00$0100a8c0@winxp> <3CB8396D.55A28D65@loewe-komp.de>
Subject: Re: read proc entry
Date: Sat, 13 Apr 2002 22:07:48 +0800
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After I added *eof =1, that message appears two times. How can I reduce it
only one?

----- Original Message -----
From: "Peter W?chtler" <pwaechtler@loewe-komp.de>
To: "Anthony Chee" <anthony.chee@polyu.edu.hk>
Cc: <linux-kernel@vger.kernel.org>
Sent: Saturday, April 13, 2002 9:58 PM
Subject: Re: read proc entry


> Anthony Chee wrote:
> >
> > I written the following code in a module
> >
> > static struct proc_dir_entry *test_proc;
> > test_proc = create_proc_read_entry(test_proc, 0444, NULL,
read_test_proc,
> > NULL);
> >
> > void show_kernel_message() {
> >     printk("\nkernel test\n");
> > }
> >
> > int read_test_info(char* page, char** start, off_t off, int count, int*
eof,
> > void* data) {
> >     show_kernel_message();
>
> I think you have to signal EOF
>
> *eof=1;
>
> > }
> >
> > After I use "cat /proc/test_proc", it is found that there are three
"kernel
> > test" messages
> > appear. Why it happened like this? I expected the message should be
shown
> > once.
> >
>

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