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Date: Fri, 19 Jul 2002 09:00:10 +0200
From: dalecki <dalecki@evision.ag>
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To: Rob Landley <landley@trommello.org>
CC: CaT <cat@zip.com.au>, Larry McVoy <lm@work.bitmover.com>,
       linux-kernel@vger.kernel.org
Subject: Re: Alright, I give up.  What does the "i" in "inode" stand for?
References: <200207190432.g6J4WD2366706@pimout5-int.prodigy.net> <20020718213857.E23208@work.bitmover.com> <20020719044518.GK5608@zip.com.au> <200207190532.g6J5Wia87042@pimout3-int.prodigy.net>
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Rob Landley wrote:
> On Friday 19 July 2002 12:45 am, CaT wrote:
> 
>>On Thu, Jul 18, 2002 at 09:38:57PM -0700, Larry McVoy wrote:
>>
>>>On Thu, Jul 18, 2002 at 06:33:54PM -0400, Rob Landley wrote:
>>>
>>>>I've been sitting on this question for years, hoping I'd come
>>>>across the answer, and I STILL don't know what the "i" is short for.
>>>>Somebody here has got to know this. :)
>>>
>>>Incore node, I believe.  In the original Unix code there was dinode and
>>>inode if I remember correctly, for disk node and incore node.
>>
>>That's a new one. I always thought it was 'information node' so in the
>>above it'd be disk information node and just information node.
>>
>>Makes sense to me in any case. :)

No it doesn't not. Becouse that would rather describe a super block.




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