Subject: Re: [Bluez-users] bizzare result when getting the bluetooth address
From: Marcel Holtmann <marcel@holtmann.org>
To: jan d tux <janice@asti.dost.gov.ph>
Cc: BlueZ Mailing List <bluez-users@lists.sourceforge.net>
In-Reply-To: <1075714467.1546.49.camel@Asgard>
References: <1075714467.1546.49.camel@Asgard>
Content-Type: text/plain
Message-Id: <1075722905.29899.10.camel@pegasus>
Mime-Version: 1.0
Sender: bluez-users-admin@lists.sourceforge.net
Errors-To: bluez-users-admin@lists.sourceforge.net
Date: Mon, 02 Feb 2004 12:55:05 +0100

Hi Jan,

> Can anybody help me figure out why the bluetooth address I am getting is
> not right?
> 
> What I am trying to do is get the bluetooth address of the sender/peer
> to my obex server.
> 
> Here are the obex calls I made:
> --------
> 	handle = OBEX_Init(OBEX_TRANS_BLUETOOTH, obex_event, 0);
> 
> 	BtOBEX_ServerRegister(handle, NULL, OBEX_PUSH_HANDLE);
> 
> 	btobex_accept(handle);
> 
> 	OBEX_HandleInput(handle, 1);
> 
> 	//get addresss
> 	
> 	fd = OBEX_GetFD(handle);
> 	if( fd < 0 )
> 		return 0;
> 
> 	getpeername(fd,(struct sockaddr *)&sa,&len)
> 		return 0;
> 
> 	baswap(&bdaddr, &sa.rc_bdaddr);
> 	printf("\tADDRESS: %s\n", batostr(&bdaddr));
> --------
> 
> 
> when i run the program, i was able to get the following:
>         channel: 10	
>         family: 31
>         ADDRESS 2: 00:0A:00:02:EE:69 -> this is not the bluetooth
> address of the sender!!! Its address is 00:02:EE:69:E1:88. The last for
> digits displayed are the 1st four digits of the device's real address. I
> tried it with another device and the result is the same, from the
> original address (00:E0:03:74:38:8E) to 00:0A:00:E0:03:74.

insert a "len = sizeof(sa)" before you call getpeername().

Regards

Marcel


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