One major difference I've noticed is the interaction with the VM subsystem.
When you have a large number of processes mmap'ing large files to send(), it
really starts to tickle bugs and performance problems. sendfile() avoids
this, only needing to use the page cache.
-joe
----- Original Message -----
From: "Mark Mielke" <[email protected]>
To: "P?l Halvorsen" <[email protected]>
Cc: "bert hubert" <[email protected]>; <[email protected]>
Sent: Thursday, May 01, 2003 12:28 AM
Subject: Re: sendfile
> On Thu, May 01, 2003 at 12:34:32AM +0200, P?l Halvorsen wrote:
> > On Wed, 30 Apr 2003, Mark Mielke wrote:
> > > To some degree, couldn't sendto() fit this description? (Assuming the
> > > kernel implemented 'zero-copy' on sendto()) The benefit of sendfile()
> > > is that data isn't coming from a memory location. It is coming from
disk,
> > > meaning that your process doesn't have to become active in order for
work
> > > to be done. In the case of UDP packets, you almost always want a layer
on
> > > top that either times the UDP packet output, or sends output in
response
> > > to input, mostly defeating the purpose of sendfile()...
> > Maybe, but then I'll have two system calls...
>
> As I mentioned before, the real benefit to sendfile(), as I understand it,
is
> that sendfile() makes it unnecessary for the OS to fully activate the
calling
> process in order to do work for the calling process. Unless you can point
out
> some other benefit provided by sendfile(), I fail to see how you will do:
>
> while (1) {
> send_frame_over_udp();
> sleep();
> }
>
> Without two system calls. Whether send_frame_over_udp() uses sendfile() as
> you seem to want it to, or whether it just calls sendto(), doesn't make a
> difference. Because one of your requirements is that you need to provide a
> smooth feed, the primary benefit of sendfile(), that of not having to
activate
> your process, becomes invalid.
>
> I haven't done timings, or looked deeply at this part of linux-2.5.x,
> however, I fail to see why the following code should not meet your
> requirements:
>
> void *p = mmap(0, length_of_file, PROT_READ, MAP_SHARED, fd, 0);
> off_t offset = 0;
>
> while (offset < length_of_file)
> {
> int packet_size = max(512, length_of_file - offset);
> send(socket, &p[offset], packet_size, 0);
> offset += packet_size;
> usleep(packets_size * 1000000 / packets_per_second);
> }
>
> In theory, send() should be able to provide the zero copy benefits you
> are requesting. In practice, it might be a little harder, but in this
> case, from my perspective, send() and sendfile() should both provide
> equivalent performance. Why would sendfile() perform better than send()?
>
> mark
>
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