Hi,
I am learning device driver only now. I was going
through the source code in via-rhine.c. What I
understand till now is that in Memory-mapped devices,
I/O operation is performed using
read(b/w/l)/write(b/w/l) functions while in IO mapped
devices it is done using in/out(b/w/l). Am I right?
But in via-rhine.c I notice use of inb and outb even
in memory mapped case(code is shown below)
------------------------------------------------------
#ifdef USE_MEM
530 static void __devinit enable_mmio(long ioaddr, int
chip_id)
531 {
532 int n;
533 if (chip_id == VT3043 || chip_id ==
VT86C100A) {
534 /* More recent docs say that this
bit is reserved ... */
535 n = inb(ioaddr + ConfigA) | 0x20;
536 outb(n, ioaddr + ConfigA);
537 } else if (chip_id == VT6102) {
538 n = inb(ioaddr + ConfigD) | 0x80;
539 outb(n, ioaddr + ConfigD);
540 }
541 }
542 #endif
-----------------------------------------------------
Can anyone tell me how does it work here? Also, don't
we need to allocate I/O ports(using request_region() )
before performing any inb/outb operations?
Please advise.
Thanks & regards,
Deepika
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You should ask this kind of questions on the kernelnewbies list.
On Mon, 19 May 2003 12:43:17 -0700, Pawan Deepika wrote:
> through the source code in via-rhine.c. What I
> understand till now is that in Memory-mapped devices,
> I/O operation is performed using
> read(b/w/l)/write(b/w/l) functions while in IO mapped
> devices it is done using in/out(b/w/l). Am I right?
What you do with inb etc. is called PIO (Programmed I/O).
> But in via-rhine.c I notice use of inb and outb even
> in memory mapped case(code is shown below)
>
> ------------------------------------------------------
> #ifdef USE_MEM
> 530 static void __devinit enable_mmio(long ioaddr, int
> chip_id)
> 531 {
It does exactly what the function name says: it uses PIO to flip a bit in
some register to enable MMIO, which is just a different (and better) way to
transfer the data.
Roger