From: Abhijeet Dharmapurikar <[email protected]>
Unless gic_ack_irq is called from __do_IRQ, interrupt should not
be disabled in the ack function. Disabling the interrupt causes
handle_edge_irq to never enable it again.
Signed-off-by: Abhijeet Dharmapurikar <[email protected]>
Signed-off-by: Jeff Ohlstein <[email protected]>
---
arch/arm/common/gic.c | 31 ++++++++++++++++++-------------
1 files changed, 18 insertions(+), 13 deletions(-)
diff --git a/arch/arm/common/gic.c b/arch/arm/common/gic.c
index 337741f..1ac2f31 100644
--- a/arch/arm/common/gic.c
+++ b/arch/arm/common/gic.c
@@ -67,25 +67,30 @@ static inline unsigned int gic_irq(unsigned int irq)
/*
* Routines to acknowledge, disable and enable interrupts
- *
- * Linux assumes that when we're done with an interrupt we need to
- * unmask it, in the same way we need to unmask an interrupt when
- * we first enable it.
- *
- * The GIC has a separate notion of "end of interrupt" to re-enable
- * an interrupt after handling, in order to support hardware
- * prioritisation.
- *
- * We can make the GIC behave in the way that Linux expects by making
- * our "acknowledge" routine disable the interrupt, then mark it as
- * complete.
*/
static void gic_ack_irq(unsigned int irq)
{
- u32 mask = 1 << (irq % 32);
spin_lock(&irq_controller_lock);
+
+#ifndef CONFIG_GENERIC_HARDIRQS_NO__DO_IRQ
+ u32 mask = 1 << (irq % 32);
+
+ /*
+ * Linux assumes that when we're done with an interrupt we need to
+ * unmask it, in the same way we need to unmask an interrupt when
+ * we first enable it.
+ *
+ * The GIC has a separate notion of "end of interrupt" to re-enable
+ * an interrupt after handling, in order to support hardware
+ * prioritisation.
+ *
+ * We can make the GIC behave in the way that Linux expects by making
+ * our "acknowledge" routine disable the interrupt, then mark it as
+ * complete.
+ */
writel(mask, gic_dist_base(irq) + GIC_DIST_ENABLE_CLEAR + (gic_irq(irq) / 32) * 4);
+#endif
writel(gic_irq(irq), gic_cpu_base(irq) + GIC_CPU_EOI);
spin_unlock(&irq_controller_lock);
}
--
1.7.1
On Thu, Jul 22, 2010 at 03:57:30PM -0700, Jeff Ohlstein wrote:
> Unless gic_ack_irq is called from __do_IRQ, interrupt should not
> be disabled in the ack function. Disabling the interrupt causes
> handle_edge_irq to never enable it again.
The GIC doesn't use handle_edge_irq.
Anyway, this change is correct since gic_ack_irq is currently doing a
maskack, when it should be just an ack. However, since
GENERIC_HARDIRQS_NO__DO_IRQ is always true on ARM, I don't see a need to
add the ifndef.
From: Abhijeet Dharmapurikar <[email protected]>
Unless gic_ack_irq is called from __do_IRQ, interrupt should not
be disabled in the ack function.
Signed-off-by: Abhijeet Dharmapurikar <[email protected]>
Signed-off-by: Jeff Ohlstein <[email protected]>
---
arch/arm/common/gic.c | 15 ---------------
1 files changed, 0 insertions(+), 15 deletions(-)
diff --git a/arch/arm/common/gic.c b/arch/arm/common/gic.c
index 337741f..9bc6d88 100644
--- a/arch/arm/common/gic.c
+++ b/arch/arm/common/gic.c
@@ -67,25 +67,10 @@ static inline unsigned int gic_irq(unsigned int irq)
/*
* Routines to acknowledge, disable and enable interrupts
- *
- * Linux assumes that when we're done with an interrupt we need to
- * unmask it, in the same way we need to unmask an interrupt when
- * we first enable it.
- *
- * The GIC has a separate notion of "end of interrupt" to re-enable
- * an interrupt after handling, in order to support hardware
- * prioritisation.
- *
- * We can make the GIC behave in the way that Linux expects by making
- * our "acknowledge" routine disable the interrupt, then mark it as
- * complete.
*/
static void gic_ack_irq(unsigned int irq)
{
- u32 mask = 1 << (irq % 32);
-
spin_lock(&irq_controller_lock);
- writel(mask, gic_dist_base(irq) + GIC_DIST_ENABLE_CLEAR + (gic_irq(irq) / 32) * 4);
writel(gic_irq(irq), gic_cpu_base(irq) + GIC_CPU_EOI);
spin_unlock(&irq_controller_lock);
}
--
1.7.1.1
Sent by an employee of the Qualcomm Innovation Center, Inc.
The Qualcomm Innovation Center, Inc. is a member of the Code Aurora Forum.