For linear voltage mapping, the n_voltages is (max - min) / step + 1
Signed-off-by: Axel Lin <[email protected]>
---
drivers/regulator/max8907-regulator.c | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
diff --git a/drivers/regulator/max8907-regulator.c b/drivers/regulator/max8907-regulator.c
index bd3b28b..bdf21a1 100644
--- a/drivers/regulator/max8907-regulator.c
+++ b/drivers/regulator/max8907-regulator.c
@@ -286,7 +286,8 @@ static __devinit int max8907_regulator_probe(struct platform_device *pdev)
MAX8907_II2RR_VERSION_REV_B) {
pmic->desc[MAX8907_SD1].min_uV = 637500;
pmic->desc[MAX8907_SD1].uV_step = 12500;
- pmic->desc[MAX8907_SD1].n_voltages = (1425000 - 637500) / 12500;
+ pmic->desc[MAX8907_SD1].n_voltages =
+ (1425000 - 637500) / 12500 + 1;
}
for (i = 0; i < MAX8907_NUM_REGULATORS; i++) {
--
1.7.9.5
On 08/15/2012 10:26 PM, Axel Lin wrote:
> For linear voltage mapping, the n_voltages is (max - min) / step + 1
Oh yes:-(
Acked-by: Stephen Warren <[email protected]>
On Thu, Aug 16, 2012 at 12:26:02PM +0800, Axel Lin wrote:
> For linear voltage mapping, the n_voltages is (max - min) / step + 1
Applied, thanks.