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Hi,
in 2.5.59-mm8 the routing table behaves a bit strange:
# > route
Kernel IP routing table
Destination Gateway Genmask Flags Metric Ref Use Iface
rtsl-stgt-de01. * 255.255.255.255 UH 0 0 0 ppp0
192.168.1.0 * 255.255.255.0 U 0 0 0 eth0
In 2.5.59-linus an additional default route is shown. If I try to add my
default route, I get:
# > route add -net 0.0.0.0 netmask 0.0.0.0 dev ppp0 gw 213.20.223.152
SIOCADDRT: File exists
# > route
Kernel IP routing table
Destination Gateway Genmask Flags Metric Ref Use Iface
rtsl-stgt-de01. * 255.255.255.255 UH 0 0 0 ppp0
192.168.1.0 * 255.255.255.0 U 0 0 0 eth0
Nothing has changed. The route seems to be there (but invisible), because I
can access other subnets through the gateway.
- --
Flo
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Florian Schmitt <[email protected]> wrote:
>
> in 2.5.59-mm8 the routing table behaves a bit strange:
me too:
vmm:/home/akpm# ip route show
192.168.2.0/24 dev eth0 scope link
127.0.0.0/8 dev lo scope link
default via 192.168.2.1 dev eth0
vmm:/home/akpm# route -n
Kernel IP routing table
Destination Gateway Genmask Flags Metric Ref Use Iface
192.168.2.0 0.0.0.0 255.255.255.0 U 0 0 0 eth0
127.0.0.0 0.0.0.0 255.0.0.0 U 0 0 0 lo
vmm:/home/akpm# route del default
vmm:/home/akpm# route del default
SIOCDELRT: No such process
So `ip' can see the default route, but `route' cannot.
Reverting the spurious semicolon fix fixes it up.
diff -puN net/ipv4/fib_hash.c~a net/ipv4/fib_hash.c
--- 25/net/ipv4/fib_hash.c~a 2003-02-09 03:04:29.000000000 -0800
+++ 25-akpm/net/ipv4/fib_hash.c 2003-02-09 03:04:32.000000000 -0800
@@ -941,7 +941,7 @@ static __inline__ struct fib_node *fib_g
if (!iter->zone)
goto out;
- if (iter->zone->fz_next)
+ if (iter->zone->fz_next);
break;
}
_