2022-02-09 09:43:42

by Jia-Ju Bai

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Subject: [BUG] ipw2100: possible deadlocks involving waiting and locking operations

Hello,

My static analysis tool reports two possible deadlock in the ipw2100
driver in Linux 5.16:

#BUG 1
ipw2100_wx_set_retry()
  mutex_lock(&priv->action_mutex); --> Line 7323 (Lock A)
  ipw2100_set_short_retry()
    ipw2100_hw_send_command()
      wait_event_interruptible_timeout(priv->wait_command_queue, ...)
--> Line 793 (Wait X)

ipw_radio_kill_sw()
  mutex_lock(&priv->action_mutex); --> Line 4259 (Lock A)
  schedule_reset()
    wake_up_interruptible(&priv->wait_command_queue); --> Line 706 (Wake X)

#BUG 2
ipw2100_wx_set_scan()
  mutex_lock(&priv->action_mutex); --> Line 7393 (Lock A)
  ipw2100_start_scan()
    ipw2100_hw_send_command()
      wait_event_interruptible_timeout(priv->wait_command_queue, ...)
--> Line 793 (Wait X)

ipw_radio_kill_sw()
  mutex_lock(&priv->action_mutex); --> Line 4259 (Lock A)
  schedule_reset()
    wake_up_interruptible(&priv->wait_command_queue); --> Line 706 (Wake X)

When ipw2100_wx_set_retry() or ipw2100_wx_set_scan() is executed, "Wait
X" is performed by holding "Lock A". If ipw_radio_kill_sw() is executed
at this time, "Wake X" cannot be performed to wake up "Wait X", because
"Lock A" has been already hold, causing possible deadlocks.
I find that "Wait X" is performed with a timeout, to relieve the
possible deadlocks; but I think this timeout can cause inefficient
execution.

I am not quite sure whether these possible problems are real.
Any feedback would be appreciated, thanks :)


Best wishes,
Jia-Ju Bai