Hi,
The attached patch (against 2.6.6) provides dynamic channel allocation
for RFComm listening sockets. This means that you can bind to channel #0
and the kernel will allocate a channel for you when you call listen() on
it. Retrieve the allocated channel number via getsockname().
The only query I have is what to return if there are no free channels.
Is ENOMEM right?
Steve
--
Stephen Crane, Rococo Software Ltd. http://www.rococosoft.com
[email protected] +353-1-6601315 (ext 209)
Hi,
does the dynamic rfcomm channel allocation work? I'm running 2.6.7-mh1
and I allways get channel 1, which is used (listend and connected) by a
other process. I don't get any error it just binds and listens on
channel 1.
cat /proc/bluetooth/rfcomm/sock
/* created thru: rfcomm listen /dev/rfcomm0 1 */
00:00:00:00:00:00 00:00:00:00:00:00 4 1
00:00:00:00:00:00 00:00:00:00:00:00 2 0
/* created thru: running my server */
xx:xx:xx:xx:xx:xx 00:00:00:00:00:00 4 1
my code:
server_sa.rc_family = AF_BLUETOOTH;
server_sa.rc_channel = channel;
server_sa.rc_bdaddr = self.addr;
if (bind(server, (struct sockaddr*) &server_sa, sizeof(server_sa)) < 0){
return(-1);
}
if (listen(server, 1) < 0) {
return(-1);
}
if (channel == 0) {
remote_len = sizeof(struct sockaddr_rc);
memset(&remote_sa, 0, sizeof(struct sockaddr_rc));
if (getsockname(server, (struct sockaddr*) &remote_sa, &remote_len) <
0) {
return(-1);
}
channel = remote_sa.rc_channel;
printf("bt_server(): channel %d\n", remote_sa.rc_channel); }
thanks ... Collin
--
Collin R. Mulliner <[email protected]>
BETAVERSiON Systems [http://www.betaversion.net]
info/pgp: finger [email protected]
To know recursion, you must first know recursion.
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